6.11 Suppose the loop in Exercise 6.4 is stationary but the current feeding the electromagnet that produces the magnetic field is gradually reduced so that the field decreases from its initial value of 0.3 T at the rate of 0.02 T s–1. If the cut is joined and the loop has a resistance of 1.6 Ω, how much power is dissipated by the loop as heat? What is the source of this power?
6.11 Suppose the loop in Exercise 6.4 is stationary but the current feeding the electromagnet that produces the magnetic field is gradually reduced so that the field decreases from its initial value of 0.3 T at the rate of 0.02 T s–1. If the cut is joined and the loop has a resistance of 1.6 Ω, how much power is dissipated by the loop as heat? What is the source of this power?
6.11 The area of the rectangular coil, A = 8 16 = 16
Initial value of the magnetic field, = 0.3 T
Rate of decrease of the magnetic field, = 0.02 T/s
From the relation of induced emf e = , where is the change in the flux linkage with the coil = A
Hence, e = = A = 16 = 3.2 V
Resistance in the
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Kindly go through the solution
Bv = B sin 60°
->
M = φ? /I? = (B? A? )/I? = [ (μ? I? /2R? )πR? ²]/I?
[Diagram of two concentric coils]
M = (μ? πR? ²)/ (2R? )
M ∝ R? ²/R?
(A) The magnet's entry
R =
L = 2 mH
E = 9V
Just after the switch ‘S’ is closed, the inductor acts as open circuit.
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Physics Ncert Solutions Class 12th 2023
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