6.16 (a) Obtain an expression for the mutual inductance between a long straight wire and a square loop of side a as shown in Fig. 6.21.

(b) Now assume that the straight wire carries a current of 50 A and the loop is moved to the right with a constant velocity, v = 10 m/s. Calculate the induced emf in the loop at the instant when x = 0.2 m. Take a = 0.1 m and assume that the loop has a large resistance.

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8 months ago

6.16 Let us take a small element dy in the loop, at a distance y from the long straight wire.

 

Magnetic flux associated with element dy, d  = BdA, where

dA = Area of the element dy = a dy

Magnetic flux at distance y, B = μ0I2πy , where

I = current in the wire

μ0 = Permeability of free space = 4 π*10-7 T m A-1

Therefore,

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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