6.6 A circular coil of radius 8.0 cm and 20 turns is rotated about its vertical diameter with an angular speed of 50 rad s^–1 in a uniform horizontal magnetic field of magnitude 3.0 * 10^–2 T. Obtain the maximum and average emf induced in the coil. If the coil forms a closed loop of resistance 10 Ω, calculate the maximum value of current in the coil. Calculate the average power loss due to Joule heating. Where does this power come from?

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Payal Gupta | Contributor-Level 10

8 months ago

6.6 Given,

Radius of the circular coil, r = 8.0 cm = 0.08 m

Area of the coil, A = $π r^{2}$ = $π * {0.08}^{2}$ = 20.106 $* 10^{- 3}$ $m^{2}$

Number of turns in the coil, n = 20

Angular speed, $ω$ = 50 rad/s

Magnetic field strength, B = 3.0 $* 10^{- 2}$ T

Resistance of the loop, R = 10 Ω

Maximum induced emf is given as e = n $ω A B$ = 20 $* 50 *$ 20.106 $* 10^{- 3} *$ 3.0 $* 10^{- 2}$ = 0.603 V

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Physics Ncert Solutions Class 12th 2023

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