Ask & Answer Question

Electromagnetic Induction Physics Ncert Solutions Class 12th Physics Class 12th Electromagnetic Induction

6.7 A horizontal straight wire 10 m long extending from east to west is falling with a speed of 5.0 m s^–1, at right angles to the horizontal component of the earth’s magnetic field, 0.30 × 10^–4 Wb m^–2.

(a) What is the instantaneous value of the emf induced in the wire?

(b) What is the direction of the emf?

(c) Which end of the wire is at the higher electrical potential?

1 View | Posted 4 months ago

Asked by Shiksha User

1 Answer

Answered by

Payal Gupta | Contributor-Level 10

4 months ago

6.7 Length of the wire, l = 10 m

Falling speed of the wire, v = 5 m/s

Magnetic field strength, B = 0.30 $* 10^{- 4}$ Wb/ $m^{2}$

The instantaneous emf induced in the wire, e = Blv = 0.30 $* 10^{- 4} * 10 *$ 5 = 1.5 $* 10^{- 3}$ V

Using Fleming's right hand rule, the direction of the induced emf is from West to East.

The eastern end of the wire is at a higher potential.

0 Upvotes 0 Downvotes

Similar Questions for you

An aeroplane, with its wings spread 10m, is flying at a speed of 180 km/h in a horizontal direction. The total intensity of earth’s field at that part is 2.5 × 10^-⁴Wb/m² and the angle of dip is 60°. The emf induced between the tips of the plane wings will be…………..

alok kumar singh

B_v = B sin 60°

-> $B_{v} = 2.5 \times 1 0^{- 4} \times \frac{\sqrt[]{3}}{2}$

$E m f = B_{v} \times v \times l = 2.5 \times 1 0^{- 4} \times \frac{\sqrt[]{3}}{2} \times 180 \times \frac{5}{18} \times 1 = 108.25 \times 1 0^{- 3} v o l t s$

Two conducting circular loops of radii R₁ and R₂ are placed in the same plane with their centres coinciding. If R₁ » R₂, the mutual inductance M between them will be directly proportional to:

alok kumar singh

M = φ? /I? = (B? A? )/I? = [ (μ? I? /2R? )πR? ²]/I?
[Diagram of two concentric coils]
M = (μ? πR? ²)/ (2R? )
M ∝ R? ²/R?

A small bar magnet is moved through a coil at constant speed from one end to the other. Which of the following series of observations will be seen on the galvanometer G attached across the coil?

Vishal Baghel

(A) The magnet's entry

Figure shows a circuit that contains four identical resistors with resistance R = $2.0 Ω,$ two identical inductors with inductance L = 2.0mH and an ideal battery with emf E = 9V. The current ‘i’ just after switch ‘S’ is closed will be:

Vishal Baghel

R = $2 Ω$

L = 2 mH

E = 9V

$i = \frac{ε}{2 R} = \frac{9 v}{4 Ω} = 2.25 A$

Just after the switch ‘S’ is closed, the inductor acts as open circuit.

An inductor coil stores 64J of magnetic field energy nad dissipates energy at the rate of 640W when a current of 8A is passed through it. If this coil is joined across an ideal battery, find the time constant of the circuit in seconds:

Vishal Baghel

$U_{B} = \frac{1}{2} L l^{2} . . . . . . . . . . . . (i)$

P_R = l²R

=> 640 = (8)² R

R = $10 Ω$

from (i) 64 = $\frac{1}{2} \times L \times {(8)}^{2}$

L = 2H

$l = \frac{L}{R} = \frac{2}{10} = 0.2 s e c o n d$

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
687k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

1 Answer

Similar Questions for you

Learn more about...

Most viewed information

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question