7.11 Figure 7.21 shows a series LCR circuit connected to a variable frequency 230 V source. L = 5.0 H, C = 80μF, R = 40 Ω.

(a) Determine the source frequency which drives the circuit in resonance.

(b) Obtain the impedance of the circuit and the amplitude of current at the resonating frequency.

(c) Determine the rms potential drops across the three elements of the circuit. Show that the potential drop across the LC combination is zero at the resonating frequency.

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8 months ago

7.11 Inductance of the Inductor, L = 5.0 H

Resistance of the resistor, R = 40 Ω

Capacitance of the capacitor, C = 80 μF= 80 *10-6 F

Potential of the voltage source, V = 230 V

Resonance angular frequency is given as

ωr = 1LC = 15*80*10-6 = 50 rad/s

Hence,thecircuitwillcomeinresonanceforasourcefrequencyof50rad/s

The impedance of the circuit is given as

Z = R2+(XL-XC)2 where XL = Inductive reactance and XC =

...Read more

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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