7.14 A rope of negligible mass is wound round a hollow cylinder of mass 3 kg and radius 40 cm. What is the angular acceleration of the cylinder if the rope is pulled with a force of 30 N ? What is the linear acceleration of the rope ? Assume that there is no slipping.

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    Answered by

    Vishal Baghel | Contributor-Level 10

    4 months ago

    Mass of the hollow cylinder, m = 3 kg

    Radius of the hollow cylinder, r = 40 cm = 0.4 m

    Applied force, F = 30 N

    The MI of the hollow cylinder about its axis,

    I = ω2 = 3 x 0.4 x 0.4 = 0.48 kgm2

    Torque,  ω22 = 30 x 0.4 = 12 Nm

    For angular acceleration ω12 , torque is given by

    mr2 = I x τ=Fxr or

    α / I = 12 / 0.48 = 25 rad/s

    Linear acceleration = r x τ = 0.4 x 25 = 10 m/s2

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