7.17 Keeping the source frequency equal to the resonating frequency of the series LCR circuit, if the three elements, L, C and R are arranged in parallel, show that the total current in the parallel LCR circuit is minimum at this frequency. Obtain the current rms value in each branch of the circuit for the elements and source specified in Exercise 7.11 for this frequency.

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8 months ago

7.17 Inductance of the Inductor, L = 5.0 H

Resistance of the resistor, R = 40 Ω

Capacitance of the capacitor, C = 80 μF= 80 *10-6 F

Potential of the voltage source, V = 230 V

Impedance Z of the given parallel LCR circuit is given as

1Z = 1R2+(1ωL-ωC)2 where ω = angular frequency

At resonance 1ωL-ωC = 0 or ω2 = 1LC

ω=1LC = 15*80*10-6 = 50 rad/s

The magnitud

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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