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9.20 Two strips of metal are riveted together at their ends by four rivets, each of diameter 6.0 mm. What is the maximum tension that can be exerted by the riveted strip if the shearing stress on the rivet is not to exceed 6.9 × 10⁷ Pa? Assume that each rivet is to carry one quarter of the load.

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Vishal Baghel | Contributor-Level 10

5 months ago

Diameter of the metal strip, d = 6.0 mm = 6 $\times 10^{- 3}$ m

Radius, r = d/2 = 3 $\times 10^{- 3}$ m

Maximum shearing stress = 6.9 $\times 10^{7}$ Pa = $\frac{M a x i m u m f o r c e}{A r e a}$

Maximum force = Maximum stress $\times A r e a$

= 6.9 $\times 10^{7} \times π \times r^{2}$ = 6.9 $\times 10^{7} \times π \times {(3 \times 10^{- 3})}^{2}$ = 1950.93 N

Since each rivet carries 1/4th of load,

Maximum tension on each rivet = 4 $\times 1950.93$ N = 7803.72 N

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9.20 Two strips of metal are riveted together at their ends by four rivets, each of diameter 6.0 mm. What is the maximum tension that can be exerted by the riveted strip if the shearing stress on the rivet is not to exceed 6.9 × 10⁷ Pa? Assume that each rivet is to carry one quarter of the load.

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9.20 Two strips of metal are riveted together at their ends by four rivets, each of diameter 6.0 mm. What is the maximum tension that can be exerted by the riveted strip if the shearing stress on the rivet is not to exceed 6.9 × 107 Pa? Assume that each rivet is to carry one quarter of the load.

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9.20 Two strips of metal are riveted together at their ends by four rivets, each of diameter 6.0 mm. What is the maximum tension that can be exerted by the riveted strip if the shearing stress on the rivet is not to exceed 6.9 × 10⁷ Pa? Assume that each rivet is to carry one quarter of the load.