A ball is bouncing elastically with a speed 1 m/s between walls of a railway compartment of size 10 m in a direction perpendicular to walls. The train is moving at a constant velocity of 10 m/s parallel to the direction of motion of the ball. As seen from the ground,

(a) The direction of motion of the ball changes every 10 seconds.

(b) Speed of ball changes every 10 seconds.

(c) Average speed of ball over any 20 second interval is fixed.

(d) The acceleration of ball is the same as from the train.

17 Views|Posted 7 months ago
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7 months ago

This is a multiple choice answer as classified in NCERT Exemplar

(b, c, d) velocity of ball before collision =10+1=11m/s

Speed after collision= 10-1=9m/s

As the speed is changing after travelling 10 m and speed is 1m/s hence, time duration of the changing speed is 10

Since the collision of the ball is

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According to question, we can write

 10 = 1 2 a t 2 . . . . . . . . . . . . . . . ( 1 ) a n d                        

1 0 + x = 1 2 a ( 2 t ) 2 . . . . . . . . . . . . . . . . ( 2 )  

X = 1 2 A [ ( 2 t ) 2 t 2 ] = 3 ( 1 2 a t 2 ) = 3 0 m  

 

Average speed = 4 v 2 3 v

= 4 v 3

(d) Initial velocity  = - v j ˆ

Final velocity = v i ˆ

Change in velocity  = v i ˆ - ( - v j ˆ )

= v ( i ˆ + j ˆ ) Momentum gain is along i ˆ + j ˆ

 Force experienced is along i ˆ + j ˆ

  Force experienced is in North-East direction.

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Physics NCERT Exemplar Solutions Class 11th Chapter Three 2025

Physics NCERT Exemplar Solutions Class 11th Chapter Three 2025

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