A ball is dropped from a building of height 45 m. Simultaneously another ball is thrown up with a speed 40 m/s. Calculate the relative speed of the balls as a function of time.
A ball is dropped from a building of height 45 m. Simultaneously another ball is thrown up with a speed 40 m/s. Calculate the relative speed of the balls as a function of time.
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1 Answer
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This is a short answer type question as classified in NCERT Exemplar
When the ball dropped from the building u1=0, u2=40m/s
Velocity of the dropped ball after time t
V1=u1+gt
V1 = gt
For ball thrown up u2=40m/s
Velocity of the ball after time t
V2=u2-gt
=40-gt
Relative velocity =v1-v2
=gt- [-40-gt]=40m/s
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[E] = ML2T-2
[V] = ML2T-2C-1
[P] = MLT-1
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10 =
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Force experienced is in North-East direction.
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