A ball is thrown vertically upwards with a velocity of 19.6 ms^-1 from the top of a tower. The ball strikes the ground after 6s. The height from the ground up to which the ball can rise will be $\left(\frac{k}{5}\right)m.$ The value of k is_______(use g = 9.8m/s²)

<p><img ></p><p>h = 39.2 + 19.6 = 58.8 m</p><p>Height above tower</p><p><math><mrow><mi>h</mi><mo>'</mo><mo>=</mo><mfrac><mrow><msup><mrow><mi>u</mi></mrow><mrow><mn>2</mn></mrow></msup></mrow><mrow><mn>2</mn><mi>g</mi></mrow></mfrac><mo>=</mo><mfrac><mrow><mn>1</mn><mn>9</mn><mo>.</mo><mn>6</mn><mo>×</mo><mn>1</mn><mn>9</mn><mo>.</mo><mn>6</mn></mrow><mrow><mn>2</mn><mo>×</mo><mn>9</mn><mo>.</mo><mn>8</mn></mrow></mfrac></mrow></math></p><p>= 19.6</p><p><math><mrow><mi>A</mi><mi>s</mi><mo>, </mo><mfrac><mrow><mi>k</mi></mrow><mrow><mn>5</mn></mrow></mfrac><mo>=</mo><mn>7</mn><mn>8</mn><mo>.</mo><mn>4</mn><mo>⇒</mo><mi>k</mi><mo>=</mo><mn>3</mn><mn>9</mn><mn>2</mn></mrow></math></p>

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