A Tennis ball is released from a height h and after freely falling on a wooden floor it rebounds and reaches height h2 . The velocity versus height of the ball during its motion may be represented graphically by: (graphs are drawn schematically and on not to scale)

⇒ V 2 = U 2 + 2 g S ⇒ V 2 = 0 + 2 g ( h - y ) ⇒ V 2 = 2 g h - 2 g y ⇒ V = 2 g h - 2 g y

A Tennis ball is released from a height $h$ and after freely falling on a wooden floor it rebounds and reaches height $\frac{h}{2}$ . The velocity versus height of the ball during its motion may be represented graphically by:

(graphs are drawn schematically and on not to scale)

Option 1 - (a)

Option 2 - (b)

Option 3 - (c)

Option 4 - (d)

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Answered by

Alok Kumar Singh | Contributor-Level 10

6 months ago

Correct Option - 3

Detailed Solution:

$\begin{array}{r} \Rightarrow V^{2} = U^{2} + 2 g S \\ \Rightarrow V^{2} = 0 + 2 g (h - y) \\ \Rightarrow V^{2} = 2 g h - 2 g y \\ \Rightarrow V = \sqrt[]{2 g h - 2 g y} \end{array}$

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