A ball of mass m is thrown vertically upwards. Another ball of mass 2 is thrown at an angle q with vertical. Both the balls stay in air for the same period of time. The ratio of the heights attained by the two balls respectively is 1 x .  The value of x is _______.

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    Answered by

    Payal Gupta | Contributor-Level 10

    2 months ago

     T1=2ugT2=2Vsinθg

    As, T1=T22ug=2Vsinθgu=vsinθ - (i)

    H1H2=u22g×2gv2sin2θ= (uvsinθ)2=1

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