A block of mass 10 kg, starts sliding on a surface with an initial velocity of 9.8 ms-1. The coefficient of friction between the surface and block is 0.5. The distance covered by the block before coming to rest is :
[used g = 9.8 ms-2]
A block of mass 10 kg, starts sliding on a surface with an initial velocity of 9.8 ms-1. The coefficient of friction between the surface and block is 0.5. The distance covered by the block before coming to rest is :
[used g = 9.8 ms-2]
a µg = 0.5 * 9.8 = 4.9 m/sec2
u = 9.8 m/sec
S =?
v = 0
v2 = u2 + 2as
s =
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= 0.92 * 1260 = 1161 m/s
For 2 kg block
T – 2g sin37 = 2a . (i)
For 4 kg block
4g – 2T =
2g – T = a . (ii)
T = (2g – a)
2g – a – 2g × = 2a
3a = 2g ×
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