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Electric Current Physics Current Electricity Physics Class 12th

A block of mass m slides on the wooden wedge, which in turn slides backward on the horizontal surface. The acceleration of the block with respect to the wedge is: Given m = 8 kg, M = 16kg. Assume all the surfaces shown in the figure to be frictionless.

Option 1 -

$\frac{6}{5} g$

Option 2 -

$\frac{3}{5} g$

Option 3 -

$\frac{2}{3} g$

Option 4 -

$\frac{4}{3} g$

3 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

2 months ago

Correct Option - 3

Detailed Solution:

Suppose acceleration of wedge is a and acceleration of block w. r.t. wedge is a₁ then N cos60° = Ma = 16 a -> N = 32 a

For block w.r.t. wedge

N + 8a sin 30° = 8g cos 30°

N = 8g cos 30° - 8a sin 30°

->32a = 8g cos 30° - 8a sin 30°

->a = $\frac{\sqrt[]{3}}{9} g$

Now for 8 kg,

$8 g s i n 30 ° + 8 a c o s 30 ° = m a_{1}$

$a_{1} = g \times \frac{1}{2} + \frac{\sqrt[]{3}}{9} g \times \frac{\sqrt[]{3}}{2}$

$= \frac{2}{3} g$

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A block of mass m slides on the wooden wedge, which in turn slides backward on the horizontal surface. The acceleration of the block with respect to the wedge is: Given m = 8 kg, M = 16kg. Assume all the surfaces shown in the figure to be frictionless.

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