A block of mass m slides on the wooden wedge, which in turn slides backward on the horizontal surface. The acceleration of the block with respect to the wedge is: Given m = 8 kg, M = 16kg. Assume all the surfaces shown in the figure to be frictionless.

A block of mass m slides on the wooden wedge, which in turn slides backward on the horizontal surface. The acceleration of the block with respect to the wedge is: Given m = 8 kg, M = 16kg. Assume all the surfaces shown in the figure to be frictionless.

Suppose acceleration of wedge is a and acceleration of block w. r.t. wedge is a1 then N cos60° = Ma = 16 a -> N = 32 a
For block w.r.t. wedge
N + 8a sin 30° = 8g cos 30°
N = 8g cos 30° - 8a sin 30°
->32a = 8g cos 30° - 8a sin 30°
->a =
Now for 8 kg,

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