A body of mass 2kg moves under a force of (2i + 3j + 5k)N. It starts from rest and was at the origin initially. After 4 s, its new coordinates are (8, b, 20). The value of b is --------. (Round off the Nearest Integer)
A body of mass 2kg moves under a force of (2i + 3j + 5k)N. It starts from rest and was at the origin initially. After 4 s, its new coordinates are (8, b, 20). The value of b is --------. (Round off the Nearest Integer)
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= 0.92 * 1260 = 1161 m/s
For 2 kg block
T – 2g sin37 = 2a . (i)
For 4 kg block
4g – 2T =
2g – T = a . (ii)
T = (2g – a)
2g – a – 2g × = 2a
3a = 2g ×
8m1 – 8m2 = m1 + m2
7m1 = 9m2
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