A body of mass M moving at speed V0 collides elastically with a mass 'm' at rest. After the collision, the two masses move at angles q1 and q2 with respect to the initial direction of motion of the body of mass M. The largest possible value of the ratio M/m, for which the angles q1 and q2 will be equal, is:

Option 1 - <p>3</p>
Option 2 - <p>1</p>
Option 3 - <p>2</p>
Option 4 - <p>4</p>
14 Views|Posted 7 months ago
Asked by Shiksha User
2 Answers
R
7 months ago
Correct Option - 1
Detailed Solution:

M V 0 = M V 1 + m V 2 . . . . ( i )

M V 1 = m V 2  . (ii)
M V 0 2 = M V 1 2 + m V 2 2 . (iii)
M V 0 2 = M V 1 2 + m ( M V 1 m ) 2 [ u s i n g e q n ( i i ) ]
( 1 + M m ) = 4
( M m ) m a x = 3

 

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R
7 months ago

M V 0 = M V 1 + m V 2 . . . . ( i )

? M V 1 = m V 2  . (ii)
M V 0 2 = M V 1 2 + m V 2 2 . (iii)
M V 0 2 = M V 1 2 + m ( M V 1 m ) 2 [ u s i n g ? ? e q n ( i i ) ]
( 1 + M m ) = 4
( M m ) m a x = 3

 

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