A body rolls down an inclined plane without slipping. The kinetic energy of rotation is 50% of its translational kinetic energy. The body is:

Option 1 -

Hollow cylinder

Option 2 -

Ring

Option 3 -

Solid sphere

Option 4 -

Solid Cylinder

2 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

2 months ago

Correct Option - 4

Detailed Solution:

$K_{T} = \frac{m v^{2}}{2} a n d K_{R} = \frac{l ω^{2}}{2} = \frac{l v^{2}}{2 R^{2}}$

According to question, we can write

$K_{R} = \frac{1}{2} K_{T} \Rightarrow \frac{l v^{2}}{2 R^{2}} = \frac{1}{2} \times \frac{m v^{2}}{2} \Rightarrow l = \frac{m R^{2}}{2} \Rightarrow S o l i d c y l i n d e r$

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