A boy throws a ball in air at 60° to the horizontal along a road with a speed of 10 m/s (36km/h). Another boy sitting in a passing by car observes the ball. Sketch the motion of the ball as observed by the boy in the car, if car has a speed of (18km/h). Give explanation to support your diagram.

0 3 Views | Posted 3 months ago
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    Answered by

    Vishal Baghel | Contributor-Level 10

    3 months ago

    This is a Short Answer Type Question as classified in NCERT Exemplar

    Explanation – the boy throws the ball at an angle of 60.

    Horizontal component of velocity 4cos θ = 10cos60

    =10 (1/2)

    =5m/s.

    so horizontal speed of the car is same, hence relative velocity of car and ball in the horizontal direction will be zero.  

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  a = v 0 2 R

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v? = 3tî v? = 24cos 60°î + 24sin 60°? = 12î + 12√3?
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ω = θ² + 2θ
α = (ωdω)/dθ = (θ² + 2θ) (2θ + 2)
At θ = 1rad.
ω = 3rad/s and α = 12rad/s²
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a? = v? ²/4r
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