A bullet is fired from a gun at the speed of 280 m/s in the direction ${30}^{?}$ above the horizontal. The maximum height attained by the bullet is $\left(\mathrm{g}=9.8{\mathrm{m}\mathrm{s}}^{-2},\mathrm{s}\mathrm{i}\mathrm{n}?{30}^{?}=0.5\right)$

A ball is projected from ground at angle q with the horizontal. After t = 1 s, it is moving at 45° with the horizontal and after t = 2 second, it is moving horizontally. What is speed of projection of ball? [g = 10 m s^–2]

A particle of mass m is projected with speed v at an angle of 30° with the horizontal, find its angular momentum about point of projection when it reaches its maximum height.

The trajectory of a projectile in an vertical plane is y = ax - bx², where a and b are constants and x & y are respectively the horizontal and vertical distances of the projectile from the point of projection. The angle of projection q and the maximum height attained H are respectively given by:

A fighter jet is flying horizontally at a certain with a speed of 200ms^-1. When it passes directly overhead ad anti-aircraft gun, a bullet is fired from the gun, at an angle (θ)with the horizontal, to hit the jet. If the bullet speed is 400m/s, the value of (θ)will be _____________.

A person can throw a ball upto a maximum range of 100m. How high above the ground he can  the same ball?