A charge Q is distributed over two concentric conducting thin spherical shells of radii r and R (R > r). If the surface charge densities on the two shells are equal, the electric potential at the common centre is:
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A charge Q is distributed over two concentric conducting thin spherical shells of radii r and R (R > r). If the surface charge densities on the two shells are equal, the electric potential at the common centre is:
Option 1 - <p>1 / 4πε₀) * [(R+r) / (R²+r²)] * Q</p>
Option 2 - <p>(1 / 4πε₀) * [(R+2r) / 2(R²+r²)] * Q</p>
Option 3 - <p>(1 / 4πε₀) * [(R+r) / 2(R²+r²)] * Q</p>
Option 4 - <p>(1 / 4πε₀) * [(2R+r) / (R²+r²)] * Q</p>
9 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
A
Answered by
7 months ago
Correct Option - 1
Detailed Solution:
σ4πr² + σ4πR² = Q ⇒ σ = Q/ (4π (R²+r²)
V_c = kq? /r + kq? /R = k (σ4πr²)/r + k (σ4πR²)/R = kσ4π (r+R)
= K (Q/ (R²+r²) (R+r)
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