A cube of metal is subjected to a hydrostatic pressure 4GPa. The percentage change in the length of the side of the cube is close to: (Given bulk modulus of metal, <math> <mi>B</mi> <mo>=</mo> <mn>8</mn> <mo>×</mo> <msup> <mrow> <mrow> <mn>10</mn> </mrow> </mrow> <mrow> <mrow> <mn>10</mn> </mrow> </mrow> </msup> </math> <math> <mi mathvariant="normal">P</mi> <mi mathvariant="normal">a</mi> <mo>)</mo> </math>

Sol. ↑ 1 ? (1) ε = 3 (2) ε - I r = 2.5 V ⇒ I r = 0.5 Now, IR = 2.5 ⇒ R r = 5 . ⇒ P R R r = I 2 R I 2 r = R r = 5 ⇒ P r = 0.5 5 = 0.1

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Physics Class 12th Mechanical Properties of Fluids Physics NCERT Exemplar Solutions Class 12th Chapter Ten

A cube of metal is subjected to a hydrostatic pressure 4GPa. The percentage change in the length of the side of the cube is close to: (Given bulk modulus of metal, $B = 8 \times 10^{10}$ $P a)$

Option 1 -

0.6

Option 2 -

Option 3 -

1.67

Option 4 -

20(Fluids)

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1 Answer

Answered by

alok kumar singh | Contributor-Level 10

4 months ago

Correct Option - 2

Detailed Solution:

Sol.

$\begin{array}{r} \end{array}$ $\begin{array}{r} ↑_{1}^{?} (1) ε = 3 \\ (2) ε - I r = 2.5 V \\ \Rightarrow I r = 0.5 \\ Now, IR = 2.5 \\ \Rightarrow \frac{R}{r} = 5 . \\ \Rightarrow \frac{P_{R}}{R_{r}} = \frac{I^{2} R}{I^{2} r} = \frac{R}{r} = 5 \\ \Rightarrow P_{r} = \frac{0.5}{5} = 0.1 \end{array}$

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A cube of metal is subjected to a hydrostatic pressure 4GPa. The percentage change in the length of the side of the cube is close to: (Given bulk modulus of metal, $B = 8 \times 10^{10}$ $P a)$

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A cube of metal is subjected to a hydrostatic pressure 4GPa. The percentage change in the length of the side of the cube is close to: (Given bulk modulus of metal, B = 8 × 10 10 P a )

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A cube of metal is subjected to a hydrostatic pressure 4GPa. The percentage change in the length of the side of the cube is close to: (Given bulk modulus of metal, $B = 8 \times 10^{10}$ $P a)$