A water drop of radius 1cm is broken into 729 equal droplets. If surface tension of water is 75 dyne/cm, then the gain in surface energy upto first decimal place will be:
(Given π = 3.14)
A water drop of radius 1cm is broken into 729 equal droplets. If surface tension of water is 75 dyne/cm, then the gain in surface energy upto first decimal place will be:
(Given π = 3.14)
Option 1 - <p>8.5 × 10<sup>-4</sup> J</p>
Option 2 - <p>8.2 × 10<sup>-4</sup> J </p>
Option 3 - <p>7.5 × 10<sup>-4</sup> J</p>
Option 4 - <p>5.3 × 10<sup>-4</sup> J</p>
13 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
V
Answered by
6 months ago
Correct Option - 3
Detailed Solution:
R3 = 729r3
R = 9r
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NLM 1
vT = 123.4 × 10-6m/sec
Kindly consider the following answer
After switch ‘S’ is closed
- (1)

Using KVL
- (2)
from (1) & (2)
G = 10 m/s2
Using bernaulli’s eqn
A = 10 cm2, V = 20 m/s
= 400 N.
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Physics NCERT Exemplar Solutions Class 12th Chapter Ten 2025
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