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Physics NCERT Exemplar Solutions Class 12th Chapter Six Physics Class 12th Physics NCERT Exemplar Solutions Class 12th Chapter Ten Mechanical Properties of Fluids

Two capacitors having C₁ and C₂ respectively are connected as shown in figure. Initially, capacitor C₁ is charged to a potential difference V volt by a battery. The battery is then removed and the charged capacitor C₁ is not connected to uncharged capacitor C₂ by closing the switch S. The amount of charge on the capacitor C₂, after equilibrium, is

Option 1 -

$\frac{C_{1} C_{2}}{(C_{1} + C_{2})} V$

Option 2 -

$\frac{(C_{1} + C_{2})}{C_{1} C_{2}} V$

Option 3 -

$(C_{1} + C_{2}) V$

Option 4 -

$(C_{1} - C_{2}) V$

3 Views | Posted 2 months ago

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1 Answer

Answered by

Payal Gupta | Contributor-Level 10

2 months ago

Correct Option - 1

Detailed Solution:

After switch ‘S’ is closed

$Q_{1} + Q_{2} = C_{1} V$ - (1)

Using KVL

$\frac{Q_{1}}{C_{1}} - \frac{Q_{2}}{C_{2}} = 0$

$Q_{1} = Q_{2} \frac{C_{1}}{C_{2}}$ - (2)

from (1) & (2)

$\Rightarrow Q_{2} [\frac{C_{1} + C_{2}}{C_{2}}] = C_{1} V \Rightarrow Q_{2} = (\frac{C_{1} C_{2}}{C_{1} + C_{2}}) V$

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