A disc with a flat small bottom beaker placed on it at a distance R from its center is revolving about an axis passing through the center and perpendicular to its plane with an angular velocity ω . The coefficient of static friction between the bottom of the beaker and the surface of the disc is μ  The beaker will revolve with the disc if :

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>R</mi> <mo>≤</mo> <mfrac> <mrow> <mi>μ</mi> <mi>g</mi> </mrow> <mrow> <mn>2</mn> <msup> <mrow> <mi>ω</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msup> </mrow> </mfrac> </mrow> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>R</mi> <mo>≤</mo> <mfrac> <mrow> <mi>μ</mi> <mi>g</mi> </mrow> <mrow> <msup> <mrow> <mi>ω</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msup> </mrow> </mfrac> </mrow> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>R</mi> <mo>≥</mo> <mfrac> <mrow> <mi>μ</mi> <mi>g</mi> </mrow> <mrow> <mn>2</mn> <msup> <mrow> <mi>ω</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msup> </mrow> </mfrac> </mrow> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>R</mi> <mo>≥</mo> <mfrac> <mrow> <mi>μ</mi> <mi>g</mi> </mrow> <mrow> <msup> <mrow> <mi>ω</mi> </mrow> <mrow> <mn>2</mn> </mrow> </msup> </mrow> </mfrac> </mrow> </math> </span></p>
7 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
R
6 months ago
Correct Option - 4
Detailed Solution:

F. B. D of Beaker

By NLM2         

f = m a = m ω 2 R m ω 2 R μ N R μ g / ω 2

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physics ncert solutions class 11th 2023

physics ncert solutions class 11th 2023

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