A helicopter is flying horizontally with a speed ‘v’ at an altitude ‘h’ has to drop a food packet for a man on the ground. What is the distance of helicopter from the man when the food packet is dropped?

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Projectile Motion Physics Motion in Plane Physics Class 11th

A helicopter is flying horizontally with a speed ‘v’ at an altitude ‘h’ has to drop a food packet for a man on the ground. What is the distance of helicopter from the man when the food packet is dropped?

Option 1 -

$\sqrt[]{2 g h v^{2} + h^{2}}$

Option 2 -

$\sqrt[]{\frac{2 v^{2} h}{g} + h^{2}}$

Option 3 -

$\sqrt[]{\frac{2 g h}{v^{2}}} + h^{2}$

Option 4 -

$\sqrt[]{\frac{2 g h v^{2} + 1}{h^{2}}}$

2 Views | Posted a month ago

Asked by Shiksha User

1 Answer

Answered by

Raj Pandey | Contributor-Level 9

a month ago

Correct Option - 2

Detailed Solution:

$h = \frac{1}{2} g t^{2}$

or $x = v \sqrt[]{\frac{2 h}{g}}$

So, x = vt

or, $x = v \frac{2 h}{g}$

So, dist of man from helicopter is

$\sqrt[]{h^{2} + x^{2}} = \sqrt[]{h^{2} + v^{2} \frac{2 h}{g}} = \sqrt[]{\frac{2 v^{2} h}{g} + h^{2}}$

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