A horizontal force 10 N is applied to a block as shown in figure. The mass of blocks and are 2 kg and 3 kg respectively. The blocks slide over a frictionless surface. The force exerted by block on block is :
A horizontal force 10 N is applied to a block as shown in figure. The mass of blocks and are 2 kg and 3 kg respectively. The blocks slide over a frictionless surface. The force exerted by block on block is :
Option 1 - <p><span lang="EN-IN">Zero</span></p>
Option 2 - <p><span lang="EN-IN">4 N</span></p>
Option 3 - <p><span lang="EN-IN">6 N</span></p>
Option 4 - <p><span lang="EN-IN">10 N</span></p>
8 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
Answered by
6 months ago
Correct Option - 3
Detailed Solution:
Similar Questions for you
= 0.92 * 1260 = 1161 m/s
For 2 kg block
T – 2g sin37 = 2a . (i)
For 4 kg block
4g – 2T =
2g – T = a . (ii)
T = (2g – a)
2g – a – 2g × = 2a
3a = 2g ×
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