A mass of is suspended by a rope of length , from the ceiling. A force is applied horizontally at the mid-point of the rope such that the top half of the rope makes an angle of with the vertical. Then equals: (Take and the rope to be massless)
A mass of is suspended by a rope of length , from the ceiling. A force is applied horizontally at the mid-point of the rope such that the top half of the rope makes an angle of with the vertical. Then equals: (Take and the rope to be massless)
Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mn>100</mn> <mtext> </mtext> <mi mathvariant="normal">N</mi> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mn>75</mn> <mtext> </mtext> <mi mathvariant="normal">N</mi> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mn>70</mn> <mtext> </mtext> <mi mathvariant="normal">N</mi> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mn>90</mn> <mtext> </mtext> <mi mathvariant="normal">N</mi> </math> </span></p>
6 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
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7 months ago
Correct Option - 4
Detailed Solution:
Similar Questions for you
= 0.92 * 1260 = 1161 m/s
For 2 kg block
T – 2g sin37 = 2a . (i)
For 4 kg block
4g – 2T =
2g – T = a . (ii)
T = (2g – a)
2g – a – 2g × = 2a
3a = 2g ×
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