A nuclide 1 is said to be the mirror isobar of nuclide 2 if Z1=N2 and Z2 = N1 (a) What nuclide is a mirror isobar of 1123Na ? (b) Which nuclide out of the two mirror isobars have greater binding energy and why?

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  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    4 months ago

    This is a Short Answer Type Questions as classified in NCERT Exemplar

    Explanation- a nuclide 1 is said to be mirror isobar of nuclide 2, if Z1=N2 and Z2= N1

    Now 11Na23, 12Mg23 for which Z2=12=N1 and N2 =23-12=11=Z1

    (b) As 12Mg23 contain even number of protons against 11Na23 which has odd number of protons (11), therefore Mg has greater binding energy than sodium.

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