A nuclide 1 is said to be the mirror isobar of nuclide 2 if Z1=N2 and Z2 = N1 (a) What nuclide is a mirror isobar of 1123Na ? (b) Which nuclide out of the two mirror isobars have greater binding energy and why?
A nuclide 1 is said to be the mirror isobar of nuclide 2 if Z1=N2 and Z2 = N1 (a) What nuclide is a mirror isobar of 1123Na ? (b) Which nuclide out of the two mirror isobars have greater binding energy and why?
-
1 Answer
-
This is a Short Answer Type Questions as classified in NCERT Exemplar
Explanation- a nuclide 1 is said to be mirror isobar of nuclide 2, if Z1=N2 and Z2= N1
Now 11Na23, 12Mg23 for which Z2=12=N1 and N2 =23-12=11=Z1
(b) As 12Mg23 contain even number of protons against 11Na23 which has odd number of protons (11), therefore Mg has greater binding energy than sodium.
Similar Questions for you
Q = [4 *4.0026 – 15.9994] *931.5 MeV
Q = 10.2 MeV
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 686k Reviews
- 1800k Answers
