A nuclide 1 is said to be the mirror isobar of nuclide 2 if Z1=N2 and Z2 = N1 (a) What nuclide is a mirror isobar of 1123Na ? (b) Which nuclide out of the two mirror isobars have greater binding energy and why?
A nuclide 1 is said to be the mirror isobar of nuclide 2 if Z1=N2 and Z2 = N1 (a) What nuclide is a mirror isobar of 1123Na ? (b) Which nuclide out of the two mirror isobars have greater binding energy and why?
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1 Answer
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This is a Short Answer Type Questions as classified in NCERT Exemplar
Explanation- a nuclide 1 is said to be mirror isobar of nuclide 2, if Z1=N2 and Z2= N1
Now 11Na23, 12Mg23 for which Z2=12=N1 and N2 =23-12=11=Z1
(b) As 12Mg23 contain even number of protons against 11Na23 which has odd number of protons (11), therefore Mg has greater binding energy than sodium.
Similar Questions for you
Q = [4 *4.0026 – 15.9994] *931.5 MeV
Q = 10.2 MeV
-(1)
for B,
for B,
-(2)
The reaction is X²? → Y¹²? + Z¹²?
Binding energies per nucleon are: X=7.6 MeV, Y=8.5 MeV, Z=8.5 MeV.
Gain in binding energy (Q) = (Binding energy of products) - (Binding energy of reactants)
Q = (120 × 8.5 + 120 × 8.5) - (240 × 7.6) MeV
Q = (2 × 120 × 8.5) - (240 × 7.6) MeV = 2040 - 1824 = 216 MeV.
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