A particle executives simple harmonic motion. Its amplitude is 8cm and time period is 6s. The time it will take to travel from its position of maximum displacement to the point corresponding to half of its amplitude, is………… s.

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Payal Gupta | Contributor-Level 10

6 months ago

A = 8 cm

T = 6 sec

q = 60° from A to B

During reaching the point its maximum amplitude from point (A)

$θ = 60 ° = \frac{π^{C}}{3}$

$θ = ω t$

$\frac{π}{3} = \frac{2 π}{6} t$

t = 1 sec

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