A particle of mass m with an initial velocity ui collides perfectly elastically with a mass 3m at rest. It moves with a velocity vj after collision, then v is given by
A particle of mass m with an initial velocity ui collides perfectly elastically with a mass 3m at rest. It moves with a velocity vj after collision, then v is given by
Option 1 - <p>v = u/√2<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>v = u/√6</p>
Option 3 - <p>v = u/3</p>
Option 4 - <p>v = 2u/√3</p>
3 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
Answered by
6 months ago
Correct Option - 1
Detailed Solution:
From momentum conservation
mui + 0 = mvj + 3mv'
v' = u/3 I - v/3 j
From kinetic energy conservation 1/2 mu² = 1/2 mv² + 1/2 (3m) (u/3)²+ (v/3)²)
Solving, v = u/√2
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