A particle slides down a frictionless parabolic (y + x2 ) track (A – B – C) starting from rest at point A (Fig. 4.2). Point B is at the vertex of parabola and point C is at a height less than that of point A. After C, the particle moves freely in air as a projectile. If the particle reaches highest point at P, then

(a) KE at P = KE at B

(b) Height at P = height at A

(c) Total energy at P = total energy at A

(d) Time of travel from A to B = time of travel from B to P.

0 1 View | Posted 3 months ago
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    Answered by

    Vishal Baghel | Contributor-Level 10

    3 months ago

    This is a Multiple Choice Questions as classified in NCERT Exemplar

    Answer- c

    Explanation– as the given track y=x2 is a frictionless track thus total energy will be same throughout the journey.

    Hence total energy at A = total energy at P . at B the particle is having only Ke but at P some KE is converted to P

    Hence (KE)B = (KE)P

    Total energy at A = PE= total energy at B = KE= total energy at P

    = PE+KE

    Potential energy at A is converted to KE and PE at P hence

    (PE)P< (PE)A

    Hence (height)P= (height)A

    As height of p < height of A

    Hence path length AB > path length BP

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