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A potentiometer wire PQ of 1 m length is connected to a standard cell E₁. Another cell E₂ of emf 1.02 V is connected with a resistance 'r' and switch S (as shown in figure). With switch S open, the null position is obtained at a distance of 49 cm from Q. The potential gradient in the potentiometer wire is:

 


Option 1 -

0.04 V/cm

Option 2 -

0.01 V/cm

Option 3 -

0.02 V/cm

Option 4 -

0.03 V/cm

0 3 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 3


    Detailed Solution:

    V_PQ * (49/100). 1.02 = V_PQ * 0.49. V_PQ ≈ 2.08V.
    Potential gradient = 2.08V/100cm = 0.0208 V/cm.

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