A pressure-pump has a horizontal tube of cross sectional area 10cm2 for the outflow of water at a speed of 20 m/s. The force exerted on the vertical wall just in front of the tube which stops water horizontally flowing out of the tube, is:

[given : density of water = 1000 kg/m3]

Option 1 - <p>300N</p>
Option 2 - <p>500N</p>
Option 3 - <p>250N</p>
Option 4 - <p>400N</p>
42 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
V
6 months ago
Correct Option - 4
Detailed Solution:

A = 10 cm2, V = 20 m/s

F=dpdt=ρAV2=103*10*104*400

= 400 N.

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.8L
Reviews
|
1.8M
Answers

Learn more about...

Physics NCERT Exemplar Solutions Class 12th Chapter Eleven 2025

Physics NCERT Exemplar Solutions Class 12th Chapter Eleven 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering