A radioactive sample has an average life of 30ms and is decaying. A capacitor of capacitance 200 µF is first charged and later connected with resistor 'R'. If the ratio of charge on capacitor to the activity of radioactive sample is fixed with respect to time then the value of 'R' should be _______ Ω.

3 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
5 months ago

 = 1/λ = 30*10? ³ sec.
C = 200µF, R
Q/A = constant [Given]
A = A? e? & Q = Q? e? /?
Q/A = (Q? /A? ) e^ (-t/RC + λt) = constant
For this to be constant, the exponent must be zero.
-t/RC + λt = 0
1/RC = λ
R = 1/ (λC) = /C = 30*10? ³/200*10? = 150 Ω

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

A = A 0 e λ t 1     [Radio active decay law]

A 5 = A 0 e λ ( t 2 t 1 )

A v e r a g e l i f e = 1 λ = ( t 2 t 1 ) l n 5  

          

...Read more

f o r A , t 1 2 = 4 s e c  

= m A 0 e 0 . 6 9 3 4 × 1 6

m A = m A 0 e 4 × 0 . 6 9 3    -(1)

for B,

for B,  t 1 2 = 8 s e c  

m B = m B 0 e 2 × 0 . 6 9 3               -(2)

m A m B = m A O m B O e 4 × 0 . 6 9 3 e 2 × 0 . 6 9 3

m A m B = 2 5 1 0 0 = x 1 0 0 x = 2 5

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering