A small elastic ball of mass m is placed at the apex of a $45 °$ inclined plane as shown in the figure below. The ball is allowed to slip without friction down the plane (along the dotted line), hit the ground (as shown) and bounce along it. If the height of the inclined plane is h and the coefficient of restitution between the ball and the ground is 0.5, then the distance AB, as marked on the figure, will be N × h, where N is

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Answered by

Vishal Baghel | Contributor-Level 10

2 months ago

$R = u_{x} \times T$

$= \sqrt[]{g h} \times \frac{0.5 \sqrt[]{g h} \times 2}{g} = h$

$\Rightarrow A B = h + h = 2 h$

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