A spaceship in space sweeps stationary interplanetary dust. As a result, its mass increases at a rate dm(t)/dt =bv^2(t), where v(t) its instantaneous velocity. The instantaneous acceleration of the satellite is:

Option 1 -

Option 2 -

Option 3 -

Option 4 -

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1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

a month ago

Correct Option - 2

Detailed Solution:

dm (t)/dt = bv²
F_thrust = v ( dm/dt )
Force on satellite = -v (dm (t)/dt)
M (t)a = -v (bv²)
a = - (bv³)/M (t)

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