A system of two blocks of masses m = 2kg and M = 8kg is placed on a smooth table as shown in figure. The coefficient of static friction between two blocked is 0.5. The maximum horizontal force F that can be applied to the block of mass M so that the blocks move together will be:

Option 1 -

9.8 N

Option 2 -

39.2 N

Option 3 -

49 N

Option 4 -

49 N

8 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

2 months ago

Correct Option - 3

Detailed Solution:

Assume both the block is moving with common acceleration ‘a’ then

$a = \frac{F}{m + M} . . . . . . . (i)$

N = mg

N = 2g

$f = m a = \frac{m F}{m + M}$

For no slipping

$\Rightarrow \frac{2 F}{10} \leq g$

$F \leq 5 g$

$\begin{array}{l} F \leq 5 \times 9.8 \\ F \leq 49.0 N \end{array}$

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