A system of two blocks of masses m = 2kg and M = 8kg is placed on a smooth table as shown in figure. The coefficient of static friction between two blocked is 0.5. The maximum horizontal force F that can be applied to the block of mass M so that the blocks move together will be:
A system of two blocks of masses m = 2kg and M = 8kg is placed on a smooth table as shown in figure. The coefficient of static friction between two blocked is 0.5. The maximum horizontal force F that can be applied to the block of mass M so that the blocks move together will be:
Assume both the block is moving with common acceleration 'a' then
N = mg
N = 2g
For no slipping
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= 0.92 * 1260 = 1161 m/s
For 2 kg block
T – 2g sin37 = 2a . (i)
For 4 kg block
4g – 2T =
2g – T = a . (ii)
T = (2g – a)
2g – a – 2g × = 2a
3a = 2g ×
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