A transistor is used in an amplifier circuit in common emitter mode. If the best current changes by 100 $μ A,$ it brings a change of 10 mA is collector current. If the load resistance is 2 $k Ω$ and input resistance is 1 $k Ω,$ the value of power gain is x × 10⁴. The value of x is_____________.

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1 Answer

Answered by

alok kumar singh | Contributor-Level 10

2 months ago

Power gain = ${(\frac{Δ i_{c}}{Δ i_{b}})}^{2} \times \frac{R_{0}}{R_{i}}$

= ${(\frac{10 \times 1 0^{- 3}}{100 \times 1 0^{- 6}})}^{2} \times \frac{2}{1}$

= 2 × 104 = x × 104

= 2

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