A uniform cube of mass m and side a is placed on a frictionless horizontal surface. A vertical force F is applied to the edge as shown in Fig. Match the following (most appropriate choice):

(a) mg/4 < F mg < /2 (i) Cube will move up.

(b) F > mg/2 (ii) Cube will not exhibit motion.

(c) F > mg (iii) Cube will begin to rotate and slip at A.

(d) F = mg/4 (iv) Normal reaction effectively at a/3 from A, no motion.

0 3 Views | Posted 4 months ago
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    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    This is a short answer type question as classified in NCERT Exemplar

    Moment of force τ 1= F (a)….anticlockwise

    Moment of weight mg τ 2=mg (a/2)……. (clockwise)

    Cube will not exhibit motion then τ 1 = τ 2

    F × a = m g × a 2

    F=mg/2

    Cube will rotate when τ 1 > τ 2

    F × a > m g × a 2

    F>mg/2

    At a/3 from point A then

    mg × a 3 = F × a o r F = m g 3

    when F=mg/4 which is less then mg/3 there will be no motion.

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