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A uniform thin bar of mass 6kg and length 24 meter is bent to make an equilateral hexagon. The moment of inertia about an axis passing through the centre of mass and perpendicular to the plane hexagon is…………..× 10-1 kg m2.

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

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    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago

    Let mAB = m = 1 kg

    AB = 0.4 m =  l

    d = OM = 0 . 1 6 − 0 . 0 4 = 0 . 1 2

    d = 2 3 × 1 0 − 1  

    I A B     a b o u t     O = m l 2 1 2 + m d 2           

    ∴ l h e x a g o n , a b o u t     O = 6 [ m l 2 1 2 + m d 2 ] = m l 2 2 + 6 m d 2       

    = 1 × ( 0 . 4 ) 2 2 + 6 × 1 × ( 2 3 × 1 0 − 1 ) 2 = 0 . 1 6 2 + 6 × 4 × 3 × 1 0 − 2   

    = 0.08 + 0.72 = 0.8 kgm2 = 8 × 10-1 kgm2

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