An adult weighing 600N raises the centre of gravity of his body by 0.25 m while taking each step of 1 m length in jogging. If he jogs for 6 km, calculate the energy utilised by him in jogging assuming that there is no energy loss due to friction of ground and air. Assuming that the body of the adult is capable of converting 10% of energy intake in the form of food, calculate the energy equivalents of food that would be required to compensate energy utilised for jogging.

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Payal Gupta | Contributor-Level 10

8 months ago

This is a short answer type question as classified in NCERT Exemplar

Weight of the adult w= mg =600N

Height of each step = h = 0.25m

Total distance travelled = 6km =6000m

Total number of steps = 6000/1= 6000

Total energy utilised in jogging = n $*$ mgh

= 6000 $*$ 600 $*$ 0.25J

= 9 $* 10^{5}$ J

Since 10% of intake energy is ut

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Time of contact =0.001s

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