As per the given circuit, the value of current through the battery will be__________A.

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Raj Pandey | Contributor-Level 9

4 months ago

$\begin{array}{l} D_{1} \\ D_{3} \end{array}}$ Forward biased offer zero Resistance

D₂} Reversed biased offers Infinite Resistance

$I = \frac{v}{R} = \frac{10}{10} = 1 A m p$

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As the switch  is closed in the circuit shown in figure, current passed through it is

Raj Pandey

Let V be the potential of the junction as shown in figure. Applying junction law, we have

or $\frac{20 - V}{2} + \frac{5 - V}{4} \bar{\to} \frac{V - 0}{2}$

or $40 - 2 V + 5 - V = 2 V$ or $5 V = 45 \Rightarrow V = 9 V$

$∴ i_{3} = \frac{V}{2} = 4.5 A$

Raj Pandey

$\equiv R e q = 2.5 Ω$

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The voltage across the 10Ω resistor in the given circuit is x volt. The value of 'x' to the nearest integer is ----------.

Raj Pandey

R_eq = 10 + (50 × 20) / (50 + 20) = 170/7 Ω
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In the experiment of Ohm's law, a potential difference of 5.0V is applied across the end of a conductor of length 10.0 cm and diameter of 5.00 mm. The measured current in the conductor is 2.00 A. The maximum permissible percentage error in the resistivity of the conductor is:



Raj Pandey

From ohm's Law, V = IR = I (ρl / A) = I (ρl / (πd²/4) ⇒ ρ = (πd²V) / (4lI)
Relative error in resistivity,
Δρ/ρ = 2 (Δd/d) + ΔV/V + Δl/l + ΔI/I = 2 × (0.01/5.00) + (0.1/5.0) + (0.1/10.0) + (0.01/2000) = 0.039
Percentage error = (Δρ/ρ) × 100 = 3.9%

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