In the experiment of Ohm's law, a potential difference of 5.0V is applied across the end of a conductor of length 10.0 cm and diameter of 5.00 mm. The measured current in the conductor is 2.00 A. The maximum permissible percentage error in the resistivity of the conductor is:

Let V  be the potential of the junction as shown in figure. Applying junction law, we have

or $\frac{20-V}{2}+\frac{5-V}{4}\overline{\to }\frac{V-0}{2}$

or $40-2V+5-V=2V$ or $5V=45\Rightarrow V=9V$

$\therefore i_3=\frac{V}{2}=4.5A$

$\begin{array}{l}{D}_1\\ D_3\end{array}\}$ Forward biased offer zero Resistance

D₂} Reversed biased offers Infinite Resistance

$I=\frac{v}{R}=\frac{10}{10}=1Amp$

$\equiv Req=2.5\Omega$

$l=\frac{v}{R_{eq}}=\frac{5}{2.5}=2A$

R_eq = 10 + (50 × 20) / (50 + 20) = 170/7 Ω
⇒ I = 170 / (170/7) = 7A
⇒ x = 10 × 7 = 70V ⇒ Voltage across 10Ω resistor