As the switch S is closed in the circuit shown in figure, current passed through it is

Option 1 - 4.5 A

Option 2 - 6.0 A

Option 3 - 3.0 A

Option 4 - Zero

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Answered by

Raj Pandey | Contributor-Level 9

4 months ago

Correct Option - 1

Detailed Solution:

Let V be the potential of the junction as shown in figure. Applying junction law, we have

or $\frac{20 - V}{2} + \frac{5 - V}{4} \bar{\to} \frac{V - 0}{2}$

or $40 - 2 V + 5 - V = 2 V$ or $5 V = 45 \Rightarrow V = 9 V$

$∴ i_{3} = \frac{V}{2} = 4.5 A$

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physics ncert exemplar solution class 12th chapter one 2025

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