At a metro station, a girl walks up a stationary escalator in time t1 . If she remains stationary on the escalator, then the escalator take her up in time t2. The time taken by her to walk up on the moving escalator will be
(a) (t1 + t2)/2
(b) t1 t2/(t1– t1)
(c) t1 t1/( t1+ t1)
(d) t1–t2
At a metro station, a girl walks up a stationary escalator in time t1 . If she remains stationary on the escalator, then the escalator take her up in time t2. The time taken by her to walk up on the moving escalator will be
(a) (t1 + t2)/2
(b) t1 t2/(t1– t1)
(c) t1 t1/( t1+ t1)
(d) t1–t2
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1 Answer
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This is a multiple choice answer as classified in NCERT Exemplar
(c) in this situation we have to find net velocity with respect to the earth that will be equal to velocity of the girl plus velocity of escalator.
Let displacement is L the
Velocity of girl vg= L/t1
Velocity of escalator ve= L/t2
net velocity = velocity of escalator +velocity of girl
Vg=l/t1 and Ve=l/t2
So net velocity = L/t1+ L/t2
So t=
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Please find the solution below:
[h] = ML2T-1
[E] = ML2T-2
[V] = ML2T-2C-1
[P] = MLT-1
According to question, we can write
10 =
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(d) Initial velocity
Final velocity
Change in velocity
Momentum gain is along
Force experienced is along
Force experienced is in North-East direction.
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