At a metro station, a girl walks up a stationary escalator in time t1 . If she remains stationary on the escalator, then the escalator take her up in time t2. The time taken by her to walk up on the moving escalator will be

(a) (t1 + t2)/2

(b) t1 t2/(t1– t1)

(c) t1 t1/( t1+ t1)

(d) t1–t2

0 3 Views | Posted 3 months ago
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    Answered by

    Payal Gupta | Contributor-Level 10

    3 months ago

    This is a multiple choice answer as classified in NCERT Exemplar

    (c) in this situation we have to find net velocity with respect to the earth that will be equal to velocity of the girl plus velocity of escalator.

    Let displacement is L the

    Velocity of  girl vg= L/t1

    Velocity of escalator ve= L/t2

    net velocity = velocity of escalator +velocity of girl

    Vg=l/t1  and Ve=l/t2

    So net velocity = L/t1+ L/t2

    So t= t 1 t 2 t 1 + t 2

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