At a metro station, a girl walks up a stationary escalator in time t1 . If she remains stationary on the escalator, then the escalator take her up in time t2. The time taken by her to walk up on the moving escalator will be

(a) (t1 + t2)/2

(b) t1 t2/(t1– t1)

(c) t1 t1/( t1+ t1)

(d) t1–t2

3 Views|Posted 7 months ago
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1 Answer
P
7 months ago

This is a multiple choice answer as classified in NCERT Exemplar

(c) in this situation we have to find net velocity with respect to the earth that will be equal to velocity of the girl plus velocity of escalator.

Let displacement is L the

Velocity of  girl vg= L/t1

Velocity of escalator ve= L/t2

net vel

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According to question, we can write

 10 = 1 2 a t 2 . . . . . . . . . . . . . . . ( 1 ) a n d                        

1 0 + x = 1 2 a ( 2 t ) 2 . . . . . . . . . . . . . . . . ( 2 )  

X = 1 2 A [ ( 2 t ) 2 t 2 ] = 3 ( 1 2 a t 2 ) = 3 0 m  

 

Average speed = 4 v 2 3 v

= 4 v 3

(d) Initial velocity  = - v j ˆ

Final velocity = v i ˆ

Change in velocity  = v i ˆ - ( - v j ˆ )

= v ( i ˆ + j ˆ ) Momentum gain is along i ˆ + j ˆ

 Force experienced is along i ˆ + j ˆ

  Force experienced is in North-East direction.

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Physics NCERT Exemplar Solutions Class 11th Chapter Three 2025

Physics NCERT Exemplar Solutions Class 11th Chapter Three 2025

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