Physics Ncert Solutions Class 12th Class 12th Physics Alternating Current

At t < 0, the capacitor is charged and the switch is opened. At t = 0 the switch is closed. The shortest time T at which the charge on the capacitor will be zero is given by:

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mi>π</mi> <mroot> <mrow> <mi>L</mi> <mi>C</mi> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>

Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>3</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> <mi>π</mi> <mroot> <mrow> <mi>L</mi> <mi>C</mi> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>

Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mi>π</mi> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> <mroot> <mrow> <mi>L</mi> <mi>C</mi> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>

Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>2</mn> <mi>π</mi> <mroot> <mrow> <mi>L</mi> <mi>C</mi> </mrow> <mrow></mrow> </mroot> </mrow> </math> </span></p>

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Answered by

Alok Kumar Singh | Contributor-Level 10

4 months ago

Correct Option - 3

Detailed Solution:

The time period of LC oscillations,

$T = 2 π \sqrt[]{L C}$

The time at which charge on the capacitor will be zero is $\frac{T}{4} .$

So t $= \frac{π}{2} \sqrt[]{L C}$

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$I = Q_{0 . ω}$

$= \frac{C V}{\sqrt[]{L C}} = V \sqrt[]{\frac{C}{L}}$

$= 12 \sqrt[]{\frac{100 \times 1 0^{- 6}}{10 \times 1 0^{- 3}}}$

= 1.2 A

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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