Consider a beam of electrons (each electron with energy E0) incident on a metal surface kept in an evacuated chamber. Then,
(a) No electrons will be emitted as only photons can emit electrons
(b) Electrons can be emitted but all with an energy, E0
(c) Electrons can be emitted with any energy, with a maximum of E0– ɸ (ɸ is the work function)
(d) Electron can be omitted with energy ,with a maximum of E0
Consider a beam of electrons (each electron with energy E0) incident on a metal surface kept in an evacuated chamber. Then,
(a) No electrons will be emitted as only photons can emit electrons
(b) Electrons can be emitted but all with an energy, E0
(c) Electrons can be emitted with any energy, with a maximum of E0– ɸ (ɸ is the work function)
(d) Electron can be omitted with energy ,with a maximum of E0
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1 Answer
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This is a Multiple Choice Questions as classified in NCERT Exemplar
Answer- (d)
explanation- When a beam of electrons of energy E0 is incident on a metal surface kept in an
evacuated chamber electrons can be emitted with maximum energy E0 (due to elastic
collision) and with any energy less than E0, when part of incident energy of electron is
used in liberating the electrons from the surface of metal.
Similar Questions for you
Based on theory
z² × (13.6) (1 - ¼) = 3 × (13.6)
z = 2 . (i)
h/√2mk? = (1/2.3) × h/√2mk?
=> k? = (2.3)²k? = 5.25k? (ii)
Now, k? = E? - Φ
k? = E? - Φ = z²E? - Φ
∴ k? /k? = (10.2 - Φ)/ (4 × 10.2 - Φ) = 1/5.25
=> Φ = 3eV
- (i)
- (ii)
from (i) & (ii)
ev
hu = hu0 + K.E
Cases u = 2u0
h2u0 = hu0 + K.E1
K.E1 = hu0
- (1)
Now, cases 2
h 5u0 = hu0 + k.E2
k.E2 = 4hu0
v2 =
v2 = 2v1
This is a Short Answer Type Questions as classified in NCERT Exemplar
Sol:
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