Consider a closed loop C in a magnetic field (figure). The flux passing through the loop is defined by choosing a surface whose edge coincides with the loop and using the formula ? = B1dA1, B2dA2…. Now, if we choose two different surfaces S1 and S2 having C as their edge, would we get the same answer for flux. Justify your answer.

0 3 Views | Posted 4 months ago
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    Answered by

    Payal Gupta | Contributor-Level 10

    4 months ago

    This is a short answer type question as classified in NCERT Exemplar

    The magnetic flux linked with the surface can considered as the number of magnetic field lines passing through the surface. So, let dφ = BA represents magnetic lines in an area to. By the concept of continuity of lines cannot end or start in space, therefore the number of lines passing through surface S1 must be the same as the number of lines passing through the surface S2.Therefore, in both the cases we gets the same answer for flux.

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