Dimensional formula for thermal conductivity is (here K denotes the temperature):

Option 1 - <p><span contenteditable="false"> <math> <msup> <mrow> <mrow> <mi mathvariant="normal">M</mi> <mi mathvariant="normal">L</mi> <mi mathvariant="normal">T</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> <mn>3</mn> </mrow> </mrow> </msup> <msup> <mrow> <mrow> <mtext> </mtext> <mi mathvariant="normal">K</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> <mn>1</mn> </mrow> </mrow> </msup> </math> </span></p>
Option 2 - <p><span contenteditable="false"> <math> <msup> <mrow> <mrow> <mi mathvariant="normal">M</mi> <mi mathvariant="normal">L</mi> <mi mathvariant="normal">T</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> <mn>2</mn> </mrow> </mrow> </msup> <msup> <mrow> <mrow> <mtext> </mtext> <mi mathvariant="normal">K</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> <mn>2</mn> </mrow> </mrow> </msup> </math> </span></p>
Option 3 - <p><span contenteditable="false"> <math> <msup> <mrow> <mrow> <mi mathvariant="normal">M</mi> <mi mathvariant="normal">L</mi> <mi mathvariant="normal">T</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> <mn>2</mn> </mrow> </mrow> </msup> <mtext> </mtext> <mi mathvariant="normal">K</mi> </math> </span></p>
Option 4 - <p><span contenteditable="false"> <math> <msup> <mrow> <mrow> <mi mathvariant="normal">M</mi> <mi mathvariant="normal">L</mi> <mi mathvariant="normal">T</mi> </mrow> </mrow> <mrow> <mrow> <mo>-</mo> <mn>3</mn> </mrow> </mrow> </msup> <mtext> </mtext> <mi mathvariant="normal">K</mi> </math> </span></p>
2 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
6 months ago
Correct Option - 1
Detailed Solution:

K=QrΔxΔAT

ML2T-2 (L)L2 (θ) (T)M1L1-T-3θ-1

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physics ncert exemplar solutions class 12th chapter two 2025

physics ncert exemplar solutions class 12th chapter two 2025

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